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Redis中redis-cluster如何删除指定的key-创新互联
这篇文章主要为大家展示了“Redis中redis-cluster如何删除指定的key”，内容简而易懂，条理清晰，希望能够帮助大家解决疑惑，下面让小编带领大家一起研究并学习一下“Redis中redis-cluster如何删除指定的key”这篇文章吧。
需要从redis-cluster中删除指定的key
循环每个主节点的版本：
[root@ip-172-31-39-42 ~]# more delkey-single.py
# encoding: utf-8
import redis
import random
import string
import rediscluster
import time
all_nodes=['172.31.39.42','172.31.36.10','172.31.47.157','172.31.36.49','172.31.40.169','172.31.32.234']
def del_keys_without_pipe(newhost):
pool = redis.ConnectionPool(host=newhost, port=6379, db=0,password='inH7HkD7iXoxKZCi')
r = redis.StrictRedis(connection_pool=pool)
start_time = time.time()
result_length = 0
for key in r.scan_iter(match='user:*:type:*:news:msg', count=100):
if r.ttl(key) == -1: 如果未设置过期时间
print key
# r.delete(key)
result_length += 1
print "normal ways end at:", time.time() - start_time
print newhost,"normal ways delete numbers:", result_length
for i in all_nodes:
del_keys_without_pipe(i)
注意：循环链接只能去链接主节点，如果链接从节点会报以下的错误：
>>> for key in r.scan_iter(count=10):
... if r.ttl(key) == -1:
... print key
...
Traceback (most recent call last):
File "", line 2, in
File "/usr/lib/python2.7/site-packages/redis/client.py", line 1231, in ttl
return self.execute_command('TTL', name)
File "/usr/lib/python2.7/site-packages/redis/client.py", line 668, in execute_command
return self.parse_response(connection, command_name, **options)
File "/usr/lib/python2.7/site-packages/redis/client.py", line 680, in parse_response
response = connection.read_response()
File "/usr/lib/python2.7/site-packages/redis/connection.py", line 629, in read_response
raise response
redis.exceptions.ResponseError: MOVED 12752 172.31.32.234:6379
链接集群版本
[root@ip-172-31-39-42 ~]# more delkey-cluster.py
# encoding: utf-8
import redis
import random
import string
import rediscluster
import time
def del_keys_without_pipe():
startup_nodes = [{"host": "172.31.39.42", "port": 6379,"db":0}]
r = rediscluster.StrictRedisCluster(startup_nodes=startup_nodes, password='inH7HkD7iXoxKZCi')
start_time = time.time()
result_length = 0
for key in r.scan_iter(match='user:*:type:*:news:msg', count=100):
# r.delete(key)
result_length += 1
print "normal ways end at:", time.time() - start_time
print "normal ways delete numbers:", result_length
del_keys_without_pipe()
以上是“Redis中redis-cluster如何删除指定的key”这篇文章的所有内容，感谢各位的阅读！相信大家都有了一定的了解，希望分享的内容对大家有所帮助，如果还想学习更多知识，欢迎关注创新互联-成都网站建设公司行业资讯频道！
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