java抢购代码 java能写抢购软件吗

java抢购怎么解决先后问题

实务未完成前拒绝其他请求。但是很明显会影响效率并且有些请求可能永远拿不到这个锁。第一种方法：队列、就是将所有请求放到队列里，按照先来先处理，原则上这样所有请求最后都会被处理。但是当你处理速度长时间跟不上请求访问数，很可能会撑爆你的队列内存。

创新互联建站2013年开创至今，先为新华等服务建站，新华等地企业，进行企业商务咨询服务。为新华企业网站制作PC+手机+微官网三网同步一站式服务解决您的所有建站问题。

求java小游戏源代码

表1. CheckerDrag.java

// CheckerDrag.javaimport java.awt.*;import java.awt.event.*;public class CheckerDrag extends java.applet.Applet{ // Dimension of checkerboard square. // 棋盘上每个小方格的尺寸 final static int SQUAREDIM = 40; // Dimension of checkerboard -- includes black outline. // 棋盘的尺寸 – 包括黑色的轮廓线 final static int BOARDDIM = 8 * SQUAREDIM + 2; // Dimension of checker -- 3/4 the dimension of a square. // 棋子的尺寸 – 方格尺寸的3/4 final static int CHECKERDIM = 3 * SQUAREDIM / 4; // Square colors are dark green or white. // 方格的颜色为深绿色或者白色 final static Color darkGreen = new Color (0, 128, 0); // Dragging flag -- set to true when user presses mouse button over checker // and cleared to false when user releases mouse button. // 拖动标记 --当用户在棋子上按下鼠标按键时设为true， // 释放鼠标按键时设为false boolean inDrag = false; // Left coordinate of checkerboard's upper-left corner. // 棋盘左上角的左方向坐标 int boardx; // Top coordinate of checkerboard's upper-left corner. //棋盘左上角的上方向坐标 int boardy; // Left coordinate of checker rectangle origin (upper-left corner). // 棋子矩形原点(左上角)的左方向坐标 int ox; // Top coordinate of checker rectangle origin (upper-left corner). // 棋子矩形原点(左上角)的上方向坐标 int oy; // Left displacement between mouse coordinates at time of press and checker // rectangle origin. // 在按键时的鼠标坐标与棋子矩形原点之间的左方向位移 int relx; // Top displacement between mouse coordinates at time of press and checker // rectangle origin. // 在按键时的鼠标坐标与棋子矩形原点之间的上方向位移 int rely; // Width of applet drawing area. // applet绘图区域的宽度 int width; // Height of applet drawing area. // applet绘图区域的高度 int height; // Image buffer. // 图像缓冲 Image imBuffer; // Graphics context associated with image buffer. // 图像缓冲相关联的图形背景 Graphics imG; public void init () { // Obtain the size of the applet's drawing area. // 获取applet绘图区域的尺寸 width = getSize ().width; height = getSize ().height; // Create image buffer. // 创建图像缓冲 imBuffer = createImage (width, height); // Retrieve graphics context associated with image buffer. // 取出图像缓冲相关联的图形背景 imG = imBuffer.getGraphics (); // Initialize checkerboard's origin, so that board is centered. // 初始化棋盘的原点，使棋盘在屏幕上居中 boardx = (width - BOARDDIM) / 2 + 1; boardy = (height - BOARDDIM) / 2 + 1; // Initialize checker's rectangle's starting origin so that checker is // centered in the square located in the top row and second column from // the left. // 初始化棋子矩形的起始原点，使得棋子在第一行左数第二列的方格里居中 ox = boardx + SQUAREDIM + (SQUAREDIM - CHECKERDIM) / 2 + 1; oy = boardy + (SQUAREDIM - CHECKERDIM) / 2 + 1; // Attach a mouse listener to the applet. That listener listens for // mouse-button press and mouse-button release events. // 向applet添加一个用来监听鼠标按键的按下和释放事件的鼠标监听器 addMouseListener (new MouseAdapter () { public void mousePressed (MouseEvent e) { // Obtain mouse coordinates at time of press. // 获取按键时的鼠标坐标 int x = e.getX (); int y = e.getY (); // If mouse is over draggable checker at time // of press (i.e., contains (x, y) returns // true), save distance between current mouse // coordinates and draggable checker origin // (which will always be positive) and set drag // flag to true (to indicate drag in progress). // 在按键时如果鼠标位于可拖动的棋子上方 // （也就是contains (x, y)返回true），则保存当前 // 鼠标坐标与棋子的原点之间的距离（始终为正值）并且 // 将拖动标志设为true（用来表明正处在拖动过程中） if (contains (x, y)) { relx = x - ox; rely = y - oy; inDrag = true; } } boolean contains (int x, int y) { // Calculate center of draggable checker. // 计算棋子的中心位置 int cox = ox + CHECKERDIM / 2; int coy = oy + CHECKERDIM / 2; // Return true if (x, y) locates with bounds // of draggable checker. CHECKERDIM / 2 is the // radius. // 如果(x, y)仍处于棋子范围内则返回true // CHECKERDIM / 2为半径 return (cox - x) * (cox - x) + (coy - y) * (coy - y) CHECKERDIM / 2 * CHECKERDIM / 2; } public void mouseReleased (MouseEvent e) { // When mouse is released, clear inDrag (to // indicate no drag in progress) if inDrag is // already set. // 当鼠标按键被释放时，如果inDrag已经为true， // 则将其置为false（用来表明不在拖动过程中） if (inDrag) inDrag = false; } }); // Attach a mouse motion listener to the applet. That listener listens // for mouse drag events. //向applet添加一个用来监听鼠标拖动事件的鼠标运动监听器 addMouseMotionListener (new MouseMotionAdapter () { public void mouseDragged (MouseEvent e) { if (inDrag) { // Calculate draggable checker's new // origin (the upper-left corner of // the checker rectangle). // 计算棋子新的原点（棋子矩形的左上角） int tmpox = e.getX () - relx; int tmpoy = e.getY () - rely; // If the checker is not being moved // (at least partly) off board, // assign the previously calculated // origin (tmpox, tmpoy) as the // permanent origin (ox, oy), and // redraw the display area (with the // draggable checker at the new // coordinates). // 如果棋子（至少是棋子的一部分）没有被 // 移出棋盘，则将之前计算的原点 // (tmpox, tmpoy)赋值给永久性的原点(ox, oy)， // 并且刷新显示区域（此时的棋子已经位于新坐标上） if (tmpox boardx tmpoy boardy tmpox + CHECKERDIM boardx + BOARDDIM tmpoy + CHECKERDIM boardy + BOARDDIM) { ox = tmpox; oy = tmpoy; repaint (); } } } }); } public void paint (Graphics g) { // Paint the checkerboard over which the checker will be dragged. // 在棋子将要被拖动的位置上绘制棋盘 paintCheckerBoard (imG, boardx, boardy); // Paint the checker that will be dragged. // 绘制即将被拖动的棋子 paintChecker (imG, ox, oy); // Draw contents of image buffer. // 绘制图像缓冲的内容 g.drawImage (imBuffer, 0, 0, this); } void paintChecker (Graphics g, int x, int y) { // Set checker shadow color. // 设置棋子阴影的颜色 g.setColor (Color.black); // Paint checker shadow. // 绘制棋子的阴影 g.fillOval (x, y, CHECKERDIM, CHECKERDIM); // Set checker color. // 设置棋子颜色 g.setColor (Color.red); // Paint checker. // 绘制棋子 g.fillOval (x, y, CHECKERDIM - CHECKERDIM / 13, CHECKERDIM - CHECKERDIM / 13); } void paintCheckerBoard (Graphics g, int x, int y) { // Paint checkerboard outline. // 绘制棋盘轮廓线 g.setColor (Color.black); g.drawRect (x, y, 8 * SQUAREDIM + 1, 8 * SQUAREDIM + 1); // Paint checkerboard. // 绘制棋盘 for (int row = 0; row 8; row++) { g.setColor (((row 1) != 0) ? darkGreen : Color.white); for (int col = 0; col 8; col++) { g.fillRect (x + 1 + col * SQUAREDIM, y + 1 + row * SQUAREDIM, SQUAREDIM, SQUAREDIM); g.setColor ((g.getColor () == darkGreen) ? Color.white : darkGreen); } } } // The AWT invokes the update() method in response to the repaint() method // calls that are made as a checker is dragged. The default implementation // of this method, which is inherited from the Container class, clears the // applet's drawing area to the background color prior to calling paint(). // This clearing followed by drawing causes flicker. CheckerDrag overrides // update() to prevent the background from being cleared, which eliminates // the flicker. // AWT调用了update()方法来响应拖动棋子时所调用的repaint()方法。该方法从 // Container类继承的默认实现会在调用paint()之前，将applet的绘图区域清除 // 为背景色，这种绘制之后的清除就导致了闪烁。CheckerDrag重写了update()来 // 防止背景被清除，从而消除了闪烁。 public void update (Graphics g) { paint (g); }}

用java进行WEB开发购物网站，如何解决十秒抢购问题？谢谢！@

抢购机制可以这样：首先在页面中用，在页面中用js写settime来显示倒数十秒，然后当用户输入抢购价格后点击抢购，就给这个用户保存数据库数据中的一个临时视图的竞标价格的字段中，在这十秒内这个字段可以更新的，如果这样访问数据库很大的话，就先把出价保存在页面，然后十秒结束后按你最后输入的最高价为标准，存进数据库。最后通过便利此视图取出最高价，然后提示出价用户抢购成功。

JAVA代码

连连看java源代码

import javax.swing.*;

import java.awt.*;

import java.awt.event.*;

public class lianliankan implements ActionListener

{

JFrame mainFrame; //主面板

Container thisContainer;

JPanel centerPanel,southPanel,northPanel; //子面板

JButton diamondsButton[][] = new JButton[6][5];//游戏按钮数组

JButton exitButton,resetButton,newlyButton; //退出，重列，重新开始按钮

JLabel fractionLable=new JLabel("0"); //分数标签

JButton firstButton,secondButton; //分别记录两次被选中的按钮

int grid[][] = new int[8][7];//储存游戏按钮位置

static boolean pressInformation=false; //判断是否有按钮被选中

int x0=0,y0=0,x=0,y=0,fristMsg=0,secondMsg=0,validateLV; //游戏按钮的位置坐标

int i,j,k,n;//消除方法控制

public void init(){

mainFrame=new JFrame("JKJ连连看");

thisContainer = mainFrame.getContentPane();

thisContainer.setLayout(new BorderLayout());

centerPanel=new JPanel();

southPanel=new JPanel();

northPanel=new JPanel();

thisContainer.add(centerPanel,"Center");

thisContainer.add(southPanel,"South");

thisContainer.add(northPanel,"North");

centerPanel.setLayout(new GridLayout(6,5));

for(int cols = 0;cols 6;cols++){

for(int rows = 0;rows 5;rows++ ){

diamondsButton[cols][rows]=new JButton(String.valueOf(grid[cols+1][rows+1]));

diamondsButton[cols][rows].addActionListener(this);

centerPanel.add(diamondsButton[cols][rows]);

}

}

exitButton=new JButton("退出");

exitButton.addActionListener(this);

resetButton=new JButton("重列");

resetButton.addActionListener(this);

newlyButton=new JButton("再来一局");

newlyButton.addActionListener(this);

southPanel.add(exitButton);

southPanel.add(resetButton);

southPanel.add(newlyButton);

fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText())));

northPanel.add(fractionLable);

mainFrame.setBounds(280,100,500,450);

mainFrame.setVisible(true);

}

public void randomBuild() {

int randoms,cols,rows;

for(int twins=1;twins=15;twins++) {

randoms=(int)(Math.random()*25+1);

for(int alike=1;alike=2;alike++) {

cols=(int)(Math.random()*6+1);

rows=(int)(Math.random()*5+1);

while(grid[cols][rows]!=0) {

cols=(int)(Math.random()*6+1);

rows=(int)(Math.random()*5+1);

}

this.grid[cols][rows]=randoms;

}

}

}

public void fraction(){

fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText())+100));

}

public void reload() {

int save[] = new int[30];

int n=0,cols,rows;

int grid[][]= new int[8][7];

for(int i=0;i=6;i++) {

for(int j=0;j=5;j++) {

if(this.grid[i][j]!=0) {

save[n]=this.grid[i][j];

n++;

}

}

}

n=n-1;

this.grid=grid;

while(n=0) {

cols=(int)(Math.random()*6+1);

rows=(int)(Math.random()*5+1);

while(grid[cols][rows]!=0) {

cols=(int)(Math.random()*6+1);

rows=(int)(Math.random()*5+1);

}

this.grid[cols][rows]=save[n];

n--;

}

mainFrame.setVisible(false);

pressInformation=false; //这里一定要将按钮点击信息归为初始

init();

for(int i = 0;i 6;i++){

for(int j = 0;j 5;j++ ){

if(grid[i+1][j+1]==0)

diamondsButton[i][j].setVisible(false);

}

}

}

public void estimateEven(int placeX,int placeY,JButton bz) {

if(pressInformation==false) {

x=placeX;

y=placeY;

secondMsg=grid[x][y];

secondButton=bz;

pressInformation=true;

}

else {

x0=x;

y0=y;

fristMsg=secondMsg;

firstButton=secondButton;

x=placeX;

y=placeY;

secondMsg=grid[x][y];

secondButton=bz;

if(fristMsg==secondMsg secondButton!=firstButton){

xiao();

}

}

}

public void xiao() { //相同的情况下能不能消去。仔细分析，不一条条注释

if((x0==x (y0==y+1||y0==y-1)) || ((x0==x+1||x0==x-1)(y0==y))){ //判断是否相邻

remove();

}

else{

for (j=0;j7;j++ ) {

if (grid[x0][j]==0){ //判断第一个按钮同行哪个按钮为空

if (yj) { //如果第二个按钮的Y坐标大于空按钮的Y坐标说明第一按钮在第二按钮左边

for (i=y-1;i=j;i-- ){ //判断第二按钮左侧直到第一按钮中间有没有按钮

if (grid[x][i]!=0) {

k=0;

break;

}

else //K=1说明通过了第一次验证

}

if (k==1) {

linePassOne();

}

}

if (yj){ //如果第二个按钮的Y坐标小于空按钮的Y坐标说明第一按钮在第二按钮右边

for (i=y+1;i=j ;i++ ){ //判断第二按钮左侧直到第一按钮中间有没有按钮

if (grid[x][i]!=0){

k=0;

break;

}

else

}

if (k==1){

linePassOne();

}

}

if (y==j ) {

linePassOne();

}

}

if (k==2) {

if (x0==x) {

remove();

}

if (x0x) {

for (n=x0;n=x-1;n++ ) {

if (grid[n][j]!=0) {

k=0;

break;

}

if(grid[n][j]==0 n==x-1) {

remove();

}

}

}

if (x0x) {

for (n=x0;n=x+1 ;n-- ) {

if (grid[n][j]!=0) {

k=0;

break;

}

if(grid[n][j]==0 n==x+1) {

remove();

}

}

}

}

}

for (i=0;i8;i++ ) { //列

if (grid[i][y0]==0) {

if (xi) {

for (j=x-1;j=i ;j-- ) {

if (grid[j][y]!=0) {

k=0;

break;

}

else

}

if (k==1) {

rowPassOne();

}

}

if (xi) {

for (j=x+1;j=i;j++ ) {

if (grid[j][y]!=0) {

k=0;

break;

}

else

}

if (k==1) {

rowPassOne();

}

}

if (x==i) {

rowPassOne();

}

}

if (k==2){

if (y0==y) {

remove();

}

if (y0y) {

for (n=y0;n=y-1 ;n++ ) {

if (grid[i][n]!=0) {

k=0;

break;

}

if(grid[i][n]==0 n==y-1) {

remove();

}

}

}

if (y0y) {

for (n=y0;n=y+1 ;n--) {

if (grid[i][n]!=0) {

k=0;

break;

}

if(grid[i][n]==0 n==y+1) {

remove();

}

}

}

}

}

}

}

public void linePassOne(){

if (y0j){ //第一按钮同行空按钮在左边

for (i=y0-1;i=j ;i-- ){ //判断第一按钮同左侧空按钮之间有没按钮

if (grid[x0][i]!=0) {

k=0;

break;

}

else //K=2说明通过了第二次验证

}

}

if (y0j){ //第一按钮同行空按钮在与第二按钮之间

for (i=y0+1;i=j ;i++){

if (grid[x0][i]!=0) {

k=0;

break;

}

else

}

}

}

public void rowPassOne(){

if (x0i) {

for (j=x0-1;j=i ;j-- ) {

if (grid[j][y0]!=0) {

k=0;

break;

}

else

}

}

if (x0i) {

for (j=x0+1;j=i ;j++ ) {

if (grid[j][y0]!=0) {

k=0;

break;

}

else

}

}

}

public void remove(){

firstButton.setVisible(false);

secondButton.setVisible(false);

fraction();

pressInformation=false;

k=0;

grid[x0][y0]=0;

grid[x][y]=0;

}

public void actionPerformed(ActionEvent e) {

if(e.getSource()==newlyButton){

int grid[][] = new int[8][7];

this.grid = grid;

randomBuild();

mainFrame.setVisible(false);

pressInformation=false;

init();

}

if(e.getSource()==exitButton)

System.exit(0);

if(e.getSource()==resetButton)

reload();

for(int cols = 0;cols 6;cols++){

for(int rows = 0;rows 5;rows++ ){

if(e.getSource()==diamondsButton[cols][rows])

estimateEven(cols+1,rows+1,diamondsButton[cols][rows]);

}

}

}

public static void main(String[] args) {

lianliankan llk = new lianliankan();

llk.randomBuild();

llk.init();

}

}

//old 998 lines

//new 318 lines

现在要做个java服务器项目，功能类似淘宝的淘抢购，请问下如何通过线程来使app在用户设置的时间进行推送

客户端用AJAX定时去服务器读取信息就成了，取到信息就显示弹出窗口什么的

推送的话服务器压力太大