c++日历/为了孙曌凌，CSDN-创新互联

哈喽，今天又是一起练手代码，表示时间的，他就是c++日历代码，有5中选择，我就是自己编然后发给在座的博客们的，这次也是一个尝试，接下来。

源代码展示：   （纯属猿创）

#include

#include

#include

using namespace std;

int o;

bool prime = 1;

bool prime1 = 1;

bool prime2 = 1;

struct {

  int year;

  int month;

  int day;

}date;

int main()

{

  void op1();

  void op2();

  void op3();

  void op4();

  void op5();

  cout<< "1.显示某一年的全年日历\n";

  cout<< "2.显示某年某月的月历\n";

  cout<< "3.显示某年某月某日是星期几\n";

  cout<< "4.显示某年某月某日是该年度的第几天\n";

  cout<< "5.退出\n";

  int z;

  cout<< "请选择(0-4)"<< endl;

  cin >>z;

  switch (z)

  {

  case 1: op1();

  break;

  case 2: op2();

  break;

  case 3: op3();

  break;

  case 4: op4();

  break;

  case 5: op5();

  break;

  }

  return 0;

}

void op4()

{

  int days;

  cout<< "输入年月日"<< endl;

  cin >>date.year >>date.month >>date.day;

  switch (date.month)

  {

  case 1:days = date.day;

  break;

  case 2:days = date.day + 31;

  break;

  case 3:days = date.day + 59;

  break;

  case 4:days = date.day + 90;

  break;

  case 5:days = date.day + 120;

  break;

  case 6:days = date.day + 151;

  break;

  case 7:days = date.day + 181;

  break;

  case 8:days =date.day + 212;

  break;

  case 9:days = date.day + 243;

  break;

  case 10:days = date.day + 273;

  break;

  case 11:days = date.day + 304;

  break;

  case 12:days = date.day + 334;

  break;

  }

  cout<< date.year<< "年"<< date.month<< "月"<< date.day<< "日是本年度的第"<< days<< "天"<< endl;

}

void op3()

{

  int xq, d1;

  if (prime)

  {

  cout<< "输入年份"<< endl;

  cin >>date.year;

  cout<< "输入本月份"<< endl;

  cin >>date.month;

  cout<< "输入日份"<< endl;

  cin >>date.day;

  }

  else if (prime1)

  {

  cout<< "输入年份"<< endl;

  cin >>date.year;

  cout<< "输入本月份"<< endl;

  cin >>date.month;

  date.day = 1;

  }

  else if (prime2)

  {

  cout<< "输入年份"<< endl;

  cin >>date.year;

  }

  d1 = (date.year - 1) * 365 + (date.year - 1) / 4 - (date.year / 100) + (date.year / 400);//百度搜的公式

  xq = d1 % 7 + 1;

  switch (date.month)

  {

  case 1:date.day = date.day; break;

  case 2:date.day = date.day + 31; break;

  case 3:date.day = date.day + 59; break;

  case 4:date.day = date.day + 90; break;

  case 5:date.day = date.day + 120; break;

  case 6:date.day = date.day + 151; break;

  case 7:date.day = date.day + 181; break;

  case 8:date.day = date.day + 212; break;

  case 9:date.day = date.day + 243; break;

  case 10:date.day = date.day + 273; break;

  case 11:date.day = date.day + 304; break;

  case 12:date.day = date.day + 334; break;

  }

  if (((date.year % 4 == 0 && date.year % 100 != 0) || date.year % 400 == 0) && date.month >= 3)//判断闰年

  date.day += 1;

  xq = (xq + (date.day - 1)) % 7;

  if (xq == 0) xq = 7;

  if (prime)

  switch (xq)

  {

  case 1:cout<< "该天是星期一"<< endl; break;

  case 2:cout<< "该天是星期二"<< endl; break;

  case 3:cout<< "该天是星期三"<< endl; break;

  case 4:cout<< "该天是星期四"<< endl; break;

  case 5:cout<< "该天是星期五"<< endl; break;

  case 6:cout<< "该天是星期六"<< endl; break;

  case 7:cout<< "该天是星期日"<< endl; break;

  }

}

void op2()

{

  prime = 0;

  op3();

  int i, s;

  int a[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };

  int m = 0, b = 0;

  if ((date.year % 4 == 0 && date.year % 100 != 0) || date.year % 400 == 0) a[2] = 29;

  cout<< date.year<< "年"<< date.month<< "月"<< endl;

  i = date.month;

  cout<< "------------------------------------------"<< endl;

  cout<< "    日    一    二    三    四    五    六"<< endl;

  cout<< "------------------------------------------"<< endl;

  if (o == 7) o = 0;

  for (m = 0; m< o; m++) cout<< "      ";

  for (b = 1; b<= a[i]; b++)

  {

  cout<< setw(6)<< b;

  if ((b + o) % 7 == 0) cout<< endl;

  }

  if (b< 33) cout<< endl;

  for (m = 0; m< o; m++) cout<< " "<< endl;

  prime = 0;

}

void op1()

{

  prime1 = 0;

  for (date.month = 1; date.month<= 12; date.month++)

  {

op2();

  prime2 = 0;

  }

}

void op5()

{

  cout<< "byebye\n";

}

‘随时随的看日历’（红眼），古德白。

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